Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 122
... force to be outward from the conductor . In other words , we are led once more to ( 7-50 ) that gives the electrostatic force per unit area as always a tension , that is , in the direction of the outward normal în . If the internal ...
... force to be outward from the conductor . In other words , we are led once more to ( 7-50 ) that gives the electrostatic force per unit area as always a tension , that is , in the direction of the outward normal în . If the internal ...
Page 245
... forces on a magnetic compass needle . Ampère heard of Oersted's result and quickly found that an electric current could also exert a force on another electric current . He began a systematic study of these forces , and , by means of a ...
... forces on a magnetic compass needle . Ampère heard of Oersted's result and quickly found that an electric current could also exert a force on another electric current . He began a systematic study of these forces , and , by means of a ...
Page 332
... force on the upper sheet , which corresponds to an increase in x , as obtained from ( 18-39 ) is then found to be F = aum m дх 1 x = = Ho K 2 ( w / ) x 2 ( 18-50 ) We see that this force is in the positive â direction and thus is ...
... force on the upper sheet , which corresponds to an increase in x , as obtained from ( 18-39 ) is then found to be F = aum m дх 1 x = = Ho K 2 ( w / ) x 2 ( 18-50 ) We see that this force is in the positive â direction and thus is ...
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Common terms and phrases
Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх