## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 234

=0 (12-19) which will lead to _ 30, in exactly the way by which we obtained (l2-l4)

. In the special case of steady currents, these become Since free charges, and

thus

usually ...

=0 (12-19) which will lead to _ 30, in exactly the way by which we obtained (l2-l4)

. In the special case of steady currents, these become Since free charges, and

thus

**free currents**, are the ones over which we have some control, they areusually ...

Page 362

In (20-10), we found a current density J," = V XM, which is associated with the

presence of matter and, as we found it useful to do ... As we discussed near the

end of Section 12-2,

control, ...

In (20-10), we found a current density J," = V XM, which is associated with the

presence of matter and, as we found it useful to do ... As we discussed near the

end of Section 12-2,

**free currents**are those over which we can exert somecontrol, ...

Page 368

(In spite of the remark above about the necessity of the absence of

it is possible to extend the use of the magnetic scalar potential to cases involving

filamentary

(In spite of the remark above about the necessity of the absence of

**free currents**,it is possible to extend the use of the magnetic scalar potential to cases involving

filamentary

**free currents**. It turns out, however, that 4:," then depends on the ...### What people are saying - Write a review

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amplitude angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb’s law cross section current density current element cylinder defined dielectric displacement distance electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point Flgure flux force free currents frequency function Galilean transformation given incident induction infinitely long integral integrand length located loop Lorentz Lorentz transformation magnetic dipole magnitude material Maxwell’s equations medium normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector produced quadrupole quantities radiation radius rectangular reﬂected region relation result rotation satisfy scalar potential shown in Figure solenoid sphere substitute surface charge surface current tangential components transformation unit vacuum vector potential velocity volume write written xy plane zero