Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 234
... free charge must be conserved too and we can write which will lead to дру ... currents , these become V.J , = 0 and  · ( Jƒ1⁄2 - Jƒ1 ) = 0 ( 12-21 ) Since free charges , and thus free currents , are the ... CURRENTS 12-3 Conduction Currents.
... free charge must be conserved too and we can write which will lead to дру ... currents , these become V.J , = 0 and  · ( Jƒ1⁄2 - Jƒ1 ) = 0 ( 12-21 ) Since free charges , and thus free currents , are the ... CURRENTS 12-3 Conduction Currents.
Page 364
... currents of matter as well as free currents . We will return to this point later . The boundary conditions satisfied by the normal components of H can be most easily obtained from the fact that the normal components of B are continu ...
... currents of matter as well as free currents . We will return to this point later . The boundary conditions satisfied by the normal components of H can be most easily obtained from the fact that the normal components of B are continu ...
Page 368
... currents , as we saw in several examples ; it may seem harder , but it can be done . ( In spite of the remark above about the necessity of the absence of free currents , it is possible to extend the use of the magnetic scalar potential ...
... currents , as we saw in several examples ; it may seem harder , but it can be done . ( In spite of the remark above about the necessity of the absence of free currents , it is possible to extend the use of the magnetic scalar potential ...
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Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх