Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
From inside the book
Results 1-3 of 96
Page 56
Find the total force on a point charge q located at an arbitrary point in the xy
plane. 2-2 Four equal point charges q' are located at the corners of a square of
side a. The square lies in the yz plane with one corner at the origin and its sides ...
Find the total force on a point charge q located at an arbitrary point in the xy
plane. 2-2 Four equal point charges q' are located at the corners of a square of
side a. The square lies in the yz plane with one corner at the origin and its sides ...
Page 264
where q' is the total charge. But under these conditions, q' can be regarded as a
point charge, so that (14-28) gives the magnetic induction produced by a moving
point charge. , By comparing (14-28) with (14-6), we see that this value of B is ...
where q' is the total charge. But under these conditions, q' can be regarded as a
point charge, so that (14-28) gives the magnetic induction produced by a moving
point charge. , By comparing (14-28) with (14-6), we see that this value of B is ...
Page 575
28-22 Show that the relativistic equation of motion (28-105) can be written in the
form mo dv =,__ (V-f)v []_(v2/,,2)]l/1 dt C1 and that if I is the Lorentz force on a
point charge, q(E+vXB), the right-hand side becomes q{E+vXB—[(v-E)/c2]v}. 28-
23 ...
28-22 Show that the relativistic equation of motion (28-105) can be written in the
form mo dv =,__ (V-f)v []_(v2/,,2)]l/1 dt C1 and that if I is the Lorentz force on a
point charge, q(E+vXB), the right-hand side becomes q{E+vXB—[(v-E)/c2]v}. 28-
23 ...
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amplitude angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb’s law cross section current density current element cylinder defined dielectric displacement distance electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point Flgure flux force free currents frequency function Galilean transformation given incident induction infinitely long integral integrand length located loop Lorentz Lorentz transformation magnetic dipole magnitude material Maxwell’s equations medium normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector produced quadrupole quantities radiation radius rectangular reflected region relation result rotation satisfy scalar potential shown in Figure solenoid sphere substitute surface charge surface current tangential components transformation unit vacuum vector potential velocity volume write written xy plane zero