Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 374
... region 2 , we know from ( 20-59 ) that Jm2 = VXM2 given by ( 20-10 ) must be zero ; we can verify this from ( 20-70 ) and ( 1-88 ) and we find that Jm2p = -M2 / 3z = 0 , Jm2 = 0 , and Jm2z = p ̄1 [ ǝ ( pM2 ) / dp ] = p ̄1 [ ǝ ( Xm1 / 2 ...
... region 2 , we know from ( 20-59 ) that Jm2 = VXM2 given by ( 20-10 ) must be zero ; we can verify this from ( 20-70 ) and ( 1-88 ) and we find that Jm2p = -M2 / 3z = 0 , Jm2 = 0 , and Jm2z = p ̄1 [ ǝ ( pM2 ) / dp ] = p ̄1 [ ǝ ( Xm1 / 2 ...
Page 390
... region 2 between the conductors is filled with a nonhomogeneous material such that K K ( p / a ) where K = const . Find H and B within this region and the contribution L2 of a length / of this region to the self - inductance . 20-26 ...
... region 2 between the conductors is filled with a nonhomogeneous material such that K K ( p / a ) where K = const . Find H and B within this region and the contribution L2 of a length / of this region to the self - inductance . 20-26 ...
Page 394
... regions shown in Figure 21-3 . Region 1 is the volume between the capacitor plates , and 2 is the remainder of that enclosed by the two parallel planes which coincide in part with the plates . Regions 3 and 4 are the rest of space ; I ...
... regions shown in Figure 21-3 . Region 1 is the volume between the capacitor plates , and 2 is the remainder of that enclosed by the two parallel planes which coincide in part with the plates . Regions 3 and 4 are the rest of space ; I ...
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Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх