## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 55

Since all charge elements in the

force will have no net horizontal components IQ,' and F0 as we found above.

Since only the z component is different from zero, the total force will be in the z ...

Since all charge elements in the

**sphere**can be paired off in this way, the totalforce will have no net horizontal components IQ,' and F0 as we found above.

Since only the z component is different from zero, the total force will be in the z ...

Page 73

fmpt/>4-' <4-15> and where V(r) is the volume of the

two cases to consider. l. Outside the

and the volume of integration in (4-15) reduces to V(a), the total volume of the ...

fmpt/>4-' <4-15> and where V(r) is the volume of the

**sphere**of radius r. There aretwo cases to consider. l. Outside the

**sphere**of charge, r>a. Here p(r')=0 if r' >a,and the volume of integration in (4-15) reduces to V(a), the total volume of the ...

Page 219

because of the presence of the

is a dipole term and the dipole moment of the

Thus the conducting

because of the presence of the

**sphere**. By comparing it with (8-48), we see that itis a dipole term and the dipole moment of the

**sphere**is p=47rcoa3Eo (ll-112)Thus the conducting

**sphere**has acquired a dipole moment proportional to the ...### What people are saying - Write a review

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amplitude angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb’s law cross section current density current element cylinder defined dielectric displacement distance electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point Flgure flux force free currents frequency function Galilean transformation given incident induction infinitely long integral integrand length located loop Lorentz Lorentz transformation magnetic dipole magnitude material Maxwell’s equations medium normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector produced quadrupole quantities radiation radius rectangular reﬂected region relation result rotation satisfy scalar potential shown in Figure solenoid sphere substitute surface charge surface current tangential components transformation unit vacuum vector potential velocity volume write written xy plane zero