Electromagnetic FieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |
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Page 155
... tangential components of F : Ô × ( F2 , F1 , ) = lim ( hc ) h → 0 ( 9-16 ) We can , in fact , write our result even more explicitly in terms of the tangential components . With the use of ( 1-23 ) , THE CURL AND THE TANGENTIAL COMPONENTS ...
... tangential components of F : Ô × ( F2 , F1 , ) = lim ( hc ) h → 0 ( 9-16 ) We can , in fact , write our result even more explicitly in terms of the tangential components . With the use of ( 1-23 ) , THE CURL AND THE TANGENTIAL COMPONENTS ...
Page 156
... tangential components of F. In If we combine these results with those of the last section , we see that we have ... tangential components Fin and F1 ,. We can find the normal component of F2 from ( 9-7 ) , and its tangential component ...
... tangential components of F. In If we combine these results with those of the last section , we see that we have ... tangential components Fin and F1 ,. We can find the normal component of F2 from ( 9-7 ) , and its tangential component ...
Page 487
... tangential components of E are always continuous , according to ( 21-26 ) , we see that Etang = 0 just outside of the surface . In other words , E has no tangential component at the surface of a perfect conductor so that E must be ...
... tangential components of E are always continuous , according to ( 21-26 ) , we see that Etang = 0 just outside of the surface . In other words , E has no tangential component at the surface of a perfect conductor so that E must be ...
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Ampère's law angle assume axis bound charge boundary conditions bounding surface calculate capacitance cavity charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb's law current density cylinder defined dielectric dipole direction displacement distance E₁ electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge function given incident induction infinitely long integral integrand k₁ Laplace's equation located Lorentz transformation magnetic magnitude material Maxwell's equations medium molecule n₂ normal components obtained origin parallel plate capacitor particle perpendicular plane wave point charge polarized position vector potential difference quantities radiation rectangular refraction region result satisfy scalar scalar potential shown in Figure solenoid spherical surface charge density tangential components total charge vacuum vector potential velocity volume write written xy plane Z₂ zero Απερ дх