## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 144

or more compactly as U __ 2 2 a2¢0 eoQ— j=x,y,z k=x,y,zQjk 0 Q»: (8-68) We

can also

—— Eoj because of (5-3) so that 1 BED]-) U = — — - 8-69 EOQ 6 /'=?.y.1 k=%.y.1

...

or more compactly as U __ 2 2 a2¢0 eoQ— j=x,y,z k=x,y,zQjk 0 Q»: (8-68) We

can also

**write**this in terms of the extemal electric field E0 by noting that (8%/8j)0=—— Eoj because of (5-3) so that 1 BED]-) U = — — - 8-69 EOQ 6 /'=?.y.1 k=%.y.1

...

Page 323

If there are surface currents, we can use the other equivalent of (12-10) to

their contribution to the energy as um = % f Kf(r)-A(r)da (18-13) all space

Example Infinitely long ideal solenoid. In (15-22), we found that this system can

be ...

If there are surface currents, we can use the other equivalent of (12-10) to

**write**their contribution to the energy as um = % f Kf(r)-A(r)da (18-13) all space

Example Infinitely long ideal solenoid. In (15-22), we found that this system can

be ...

Page 4

We know from kinematics that, in such a case, we can

the vector V, in the form dv —l1TJ'=¢o¢-Xv, (A-15) Equating (A-15) with (A-1 1),

we find the vector angular velocity to be or,-_-= —(%)B (A-16) and whose sign ...

We know from kinematics that, in such a case, we can

**write**the rate of change ofthe vector V, in the form dv —l1TJ'=¢o¢-Xv, (A-15) Equating (A-15) with (A-1 1),

we find the vector angular velocity to be or,-_-= —(%)B (A-16) and whose sign ...

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amplitude angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitor charge density charge distribution charge q circuit conductor consider constant coordinates corresponding Coulomb’s law cross section current density current element cylinder defined dielectric displacement distance electric field electromagnetic electrostatic energy equal evaluate example Exercise expression field point Flgure flux force free currents frequency function Galilean transformation given incident induction infinitely long integral integrand length located loop Lorentz Lorentz transformation magnetic dipole magnitude material Maxwell’s equations medium normal components obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector produced quadrupole quantities radiation radius rectangular reﬂected region relation result rotation satisfy scalar potential shown in Figure solenoid sphere substitute surface charge surface current tangential components transformation unit vacuum vector potential velocity volume write written xy plane zero