Engineering Mechanics of Materials4. 2 Solid Circular Shafts-Angle of Twist and Shearing Stresses 159 4. 3 Hollow Circular Shafts-Angle of Twist and Shearing Stresses 166 4. 4 Principal Stresses and Strains Associated with Torsion 173 4. 5 Analytical and Experimental Solutions for Torsion of Members of Noncircular Cross Sections 179 4. 6 Shearing Stress-Strain Properties 188 *4. 7 Computer Applications 195 5 Stresses in Beams 198 5. 1 Introduction 198 5. 2 Review of Properties of Areas 198 5. 3 Flexural Stresses due to Symmetric Bending of Beams 211 5. 4 Shear Stresses in Symmetrically Loaded Beams 230 *5. 5 Flexural Stresses due to Unsymmetric Bending of Beams 248 *5. 6 Computer Applications 258 Deflections of Beams 265 I 6. 1 Introduction 265 6. 2 Moment-Curvature Relationship 266 6. 3 Beam Deflections-Two Successive Integrations 268 6. 4 Derivatives of the Elastic Curve Equation and Their Physical Significance 280 6. 5 Beam Deflections-The Method of Superposition 290 6. 6 Construction of Moment Diagrams by Cantilever Parts 299 6. 7 Beam Deflections-The Area-Moment Method 302 *6. 8 Beam Deflections-Singularity Functions 319 *6. 9 Beam Deflections-Castigliano's Second Theorem 324 *6. 10 Computer Applications 332 7 Combined Stresses and Theories of Failure 336 7. 1 Introduction 336 7. 2 Axial and Torsional Stresses 336 Axial and Flexural Stresses 342 7. 3 Torsional and Flexural Stresses 352 7. 4 7. 5 Torsional, Flexural, and Axial Stresses 358 *7. 6 Theories of Failure 365 Computer Applications 378 *7. |
From inside the book
Results 1-5 of 92
Page 2
... respect to the entire body are external when shown on these free - body diagrams . Each of these forces is assumed to be tensile at the appropriate section and a negative sign will indicate a compressive force . In order to determine FA ...
... respect to the entire body are external when shown on these free - body diagrams . Each of these forces is assumed to be tensile at the appropriate section and a negative sign will indicate a compressive force . In order to determine FA ...
Page 6
... respect to the longitudinal coordinate x . Graphically , this is as depicted in Fig . 1.4 ( c ) and ( d ) . The ordinate ƒ to the f - x curve at any point such as x = xo is equal to the slope of the F - x curve at the same point . tion ...
... respect to the longitudinal coordinate x . Graphically , this is as depicted in Fig . 1.4 ( c ) and ( d ) . The ordinate ƒ to the f - x curve at any point such as x = xo is equal to the slope of the F - x curve at the same point . tion ...
Page 16
... respect to the longitudinal coordinate x . Graphi- cally , this is depicted in Fig . 1.9 ( c ) and ( d ) . ( 0 , 0 ) ΤΑ T x1 хо X2 x ( L , 0 ) ( c ) X2 Ordinate q Area = s q dx ( a ) equals ( 0 , -TA ) q dx slope = ( d ) dT dx T2 Τι Тв ...
... respect to the longitudinal coordinate x . Graphi- cally , this is depicted in Fig . 1.9 ( c ) and ( d ) . ( 0 , 0 ) ΤΑ T x1 хо X2 x ( L , 0 ) ( c ) X2 Ordinate q Area = s q dx ( a ) equals ( 0 , -TA ) q dx slope = ( d ) dT dx T2 Τι Тв ...
Page 17
... respect to the x axis : Σ Τ = 0 T - qx + 200 = 0 T = -200 + qx This function is plotted in Fig . 1.10 ( c ) with q = 100 N - m / m . If this function is differen- tiated with respect to x , the resulting equation is given by dT dx q ...
... respect to the x axis : Σ Τ = 0 T - qx + 200 = 0 T = -200 + qx This function is plotted in Fig . 1.10 ( c ) with q = 100 N - m / m . If this function is differen- tiated with respect to x , the resulting equation is given by dT dx q ...
Page 20
... respect to the end resisting torques T and T , which ΤΑ Line loading Intensity w Тв you may assume to be equal . Line loading intensity w is expressed as force units per unit length and the eccen- tricity e is expressed in units of ...
... respect to the end resisting torques T and T , which ΤΑ Line loading Intensity w Тв you may assume to be equal . Line loading intensity w is expressed as force units per unit length and the eccen- tricity e is expressed in units of ...
Contents
Stresses in Beams | 198 |
Deflections of Beams | 265 |
Combined Stresses and Theories of Failure | 336 |
Column Theory and Analyses | 384 |
Statically Indeterminate Members | 432 |
Introduction to Component Design | 484 |
Analysis and Design for Inelastic Behavior | 523 |
Analysis and Design for Impact and Fatigue Loadings | 552 |
Selected Topics | 590 |
13 7 | 625 |
APPENDIX | 647 |
Index | 687 |
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Common terms and phrases
absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive constant coordinate cross section cross-sectional area cylinder deflection deformation depicted in Fig diameter elastic curve equal equation equilibrium Euler EXAMPLE factor of safety FIGURE flexural stress FORTRAN free-body diagram k-ft k-in kN-m lb/ft length longitudinal M₁ material maximum shear stress modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained plane stress plane stress condition plot principal centroidal axis principal stresses r₁ radius ratio Refer to Fig rotation shaft shear force shear strain shown in Fig slope SOLUTION statically indeterminate steel stress element t₁ t₂ tensile Tmax torque torsional uniform load V₁ yield stress zero σ₁