## Strength of materials |

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Page 59

Bronze

70 GPa E = 200 GPa Figures P-246 and P-247. 248. A steel tube 2.5 mm thick

just fits over an

Bronze

**Aluminum**Steel A = 2400 mm' A = 1200 mm? A=600 mm? E = 83 GPa E=70 GPa E = 200 GPa Figures P-246 and P-247. 248. A steel tube 2.5 mm thick

just fits over an

**aluminum**tube 2.5 mm thick. If the contact diameter is 100 mm, ...Page 62

Horizontal movement is prevented at joint A by the short horizontal strut AE.

Determine the stress in each bar and the force in the strut AE. For the steel bar, A

= 200 mmz and E = 200 GPa. For each

GPa.

Horizontal movement is prevented at joint A by the short horizontal strut AE.

Determine the stress in each bar and the force in the strut AE. For the steel bar, A

= 200 mmz and E = 200 GPa. For each

**aluminum**bar, A = 400 mmz and E = 70GPa.

Page 418

For example, consider the experimental section shown in Fig. l0-2a consisting of

an

using the ratio of the moduli of elasticity of the steel and bronze to that of the ...

For example, consider the experimental section shown in Fig. l0-2a consisting of

an

**aluminum**core to which plates of steel and bronze are securely attached. Byusing the ratio of the moduli of elasticity of the steel and bronze to that of the ...

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allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld