## Strength of materials |

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Page 58

It carries an

are given by R, = Pb/ L and R2 = Pa / L. (Note that these reactions are equivalent

to those of a simply supported beam carrying a concentrated load.) R, 3 P b E R ...

It carries an

**axial load**P applied as shown in Fig. P-242. Prove that the reactionsare given by R, = Pb/ L and R2 = Pa / L. (Note that these reactions are equivalent

to those of a simply supported beam carrying a concentrated load.) R, 3 P b E R ...

Page 359

9-2 COMBINED

Fig. 9-la carries a concentrated

its centroidal surface. At point A, the flexural stress of = My / I . It is tensile and is ...

9-2 COMBINED

**AXIAL**AND FLEXURAL**LOADS**The simply supported beam inFig. 9-la carries a concentrated

**load**Q. The supports are hinged to the beam atits centroidal surface. At point A, the flexural stress of = My / I . It is tensile and is ...

Page 464

Determine the safe

length is (a) 2 m and (b) 4 m. Use E = 11.5 GPa. Ans. (a) 582 kN; (b) 146 kN 1132

. Repeat Problem 1131 for a pine column 50 mm by 200 mm for which E = 11.2

GPa.

Determine the safe

**axial loads**on an oak column 150 mm by 200 mm if thelength is (a) 2 m and (b) 4 m. Use E = 11.5 GPa. Ans. (a) 582 kN; (b) 146 kN 1132

. Repeat Problem 1131 for a pine column 50 mm by 200 mm for which E = 11.2

GPa.

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allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld