## Strength of materials |

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Page 87

initially there is a 6° mismatch in the location of the

figure. Determine the maximum shearing stress in each shaft after the shafts are

bolted together. Use G = 83 GN/m2 and neglect deformations of the

initially there is a 6° mismatch in the location of the

**bolt**holes, as shown in thefigure. Determine the maximum shearing stress in each shaft after the shafts are

bolted together. Use G = 83 GN/m2 and neglect deformations of the

**bolts**and ...Page 88

Coupling with two concentric

by Y1 _ B R' — R2 (4) Using Hooke's law for shear, G = -r/7, we have ll P A P A c;

Tir ciriz °' G'/R I 0/R 2 (b) 1 1 2 2 1 1 2 2 If the

Coupling with two concentric

**bolt**circles. Thus, the shearing strains are relatedby Y1 _ B R' — R2 (4) Using Hooke's law for shear, G = -r/7, we have ll P A P A c;

Tir ciriz °' G'/R I 0/R 2 (b) 1 1 2 2 1 1 2 2 If the

**bolts**on the two circles have the ...Page 89

A flanged

300 mm in diameter, and four 10-mm-diameter steel

circle 200 mm in diameter, as shown in Fig. 3-7. What torque can be applied ...

A flanged

**bolt**coupling consists of six 10-mm-diameter steel**bolts**on a**bolt**circle300 mm in diameter, and four 10-mm-diameter steel

**bolts**on a concentric**bolt**circle 200 mm in diameter, as shown in Fig. 3-7. What torque can be applied ...

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allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld