## Strength of materials |

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Page 49

For uniaxial stress, the transverse strain is _ 6 ox l 79.6 X 10 la = ""~ = -"fl i = '§(T>

10T) = 379 X l0_° m/m Therefore, the required diametrical clearance is [8 = eL] 8y

= (379 X l0'°)(80) = 0.0303 mm The required internal

For uniaxial stress, the transverse strain is _ 6 ox l 79.6 X 10 la = ""~ = -"fl i = '§(T>

10T) = 379 X l0_° m/m Therefore, the required diametrical clearance is [8 = eL] 8y

= (379 X l0'°)(80) = 0.0303 mm The required internal

**diameter**of the tube is ...Page 82

What is the minimum

more than 3° in a 6-m length when subjected to a torque of l4 kN -m? What

maximum shearing stress is developed? Use G= 83 GN/m2. Ans. d= 118 mm;r =

43.4 ...

What is the minimum

**diameter**of a solid steel shaft that will not twist throughmore than 3° in a 6-m length when subjected to a torque of l4 kN -m? What

maximum shearing stress is developed? Use G= 83 GN/m2. Ans. d= 118 mm;r =

43.4 ...

Page 101

Determine the maximum shearing stress and elongation in a helical steel spring

composed of 20 turns of 20-mm-

the spring is supporting a load of 2 kN. Use Eq. (3-10) and G = 83 GN/m2.

Determine the maximum shearing stress and elongation in a helical steel spring

composed of 20 turns of 20-mm-

**diameter**wire on a mean radius of 80 mm whenthe spring is supporting a load of 2 kN. Use Eq. (3-10) and G = 83 GN/m2.

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