Strength of Materials |
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Page 136
... equal distances to either side of G the shear is numerically equal but of opposite sign , thereby producing equal slopes oppositely directed . The moment curve between A and B , how- ever , is not symmetrical about F because the shear ...
... equal distances to either side of G the shear is numerically equal but of opposite sign , thereby producing equal slopes oppositely directed . The moment curve between A and B , how- ever , is not symmetrical about F because the shear ...
Page 185
... ( equal to the area abcd multiplied by the average of the stresses σ and σ ) can be balanced only by a shear ... equal intervals from the top ; i.e. , although the total compressive force increases as we descend by equal intervals from the ...
... ( equal to the area abcd multiplied by the average of the stresses σ and σ ) can be balanced only by a shear ... equal intervals from the top ; i.e. , although the total compressive force increases as we descend by equal intervals from the ...
Page 298
... equal to each other , and each equals one - half the applied loads . The end moments also equal each other but are unknown . The simplest condition that determines the unknown end moment is that in a symmetrically loaded beam the ...
... equal to each other , and each equals one - half the applied loads . The end moments also equal each other but are unknown . The simplest condition that determines the unknown end moment is that in a symmetrically loaded beam the ...
Common terms and phrases
allowable stresses aluminum angle applied load assumed axial load beam carrying beam in Fig beam loaded beam shown bending moment bolt bronze cantilever beam centroid column compressive stress concentrated load continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equilibrium equivalent exploratory section factor of safety fibers free-body diagram GN/m² Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS kN.m kN·m kN/m length load diagram loaded as shown M₁ M₂ maximum shearing stress midspan deflection mm² MN/m² Mohr's circle moment of inertia N/m² neutral axis obtain P₁ P₂ plane plate positive principal stresses proportional limit R₁ R₂ R2 Figure radius reaction resisting restrained beam resultant rivet segment shaft shear diagram shearing force shown in Fig simply supported beam Solution span statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld ΕΙ