## Strength of materials |

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Page 395

which is

expressed by %(M + T.) It is not necessary to memorize Eqs. (9-ll) and (9-12)

because they are so similar to the torsion and flexure formulas. In using them ...

which is

**equivalent**to the flexure formula in Eq. (b) if the**equivalent**moment M, isexpressed by %(M + T.) It is not necessary to memorize Eqs. (9-ll) and (9-12)

because they are so similar to the torsion and flexure formulas. In using them ...

Page 417

However, by suitable modifications we can obtain an

of one material to which the theory can be applied. To obtain an

section, consider a longitudinal steel fiber of the beam at A. Since the steel and

wood ...

However, by suitable modifications we can obtain an

**equivalent**section in termsof one material to which the theory can be applied. To obtain an

**equivalent**section, consider a longitudinal steel fiber of the beam at A. Since the steel and

wood ...

Page 418

from which, by canceling out ow and denoting the ratio of the moduli of elasticity

E,/Ew by n, we finally have Aw I M, (10-1) This indicates that the area of the

area is ...

from which, by canceling out ow and denoting the ratio of the moduli of elasticity

E,/Ew by n, we finally have Aw I M, (10-1) This indicates that the area of the

**equivalent**wood is n times the area of the steel. The location of the**equivalent**area is ...

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allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld