Strength of Materials |
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Page 76
... fibers . Slice will rotate past slice D until the elastic fibers joining them are deformed enough to create a resisting torque which balances the applied torque . When this happens , slices D and will act as a rigid unit and transmit ...
... fibers . Slice will rotate past slice D until the elastic fibers joining them are deformed enough to create a resisting torque which balances the applied torque . When this happens , slices D and will act as a rigid unit and transmit ...
Page 177
... fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the centroidal or neutral axis in such a position that the ratio of the distances from it to ...
... fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the centroidal or neutral axis in such a position that the ratio of the distances from it to ...
Page 555
... fibers and the decreased stress at the outer fibers , in comparison with the stresses computed from the flexure formula . To determine the shift in position of the neutral axis and to express the stress at any fiber in terms of the ...
... fibers and the decreased stress at the outer fibers , in comparison with the stresses computed from the flexure formula . To determine the shift in position of the neutral axis and to express the stress at any fiber in terms of the ...
Common terms and phrases
allowable stresses aluminum angle applied load assumed axial load beam carrying beam in Fig beam loaded beam shown bending moment bolt bronze cantilever beam centroid column compressive stress concentrated load continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equilibrium equivalent exploratory section factor of safety fibers free-body diagram GN/m² Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS kN.m kN·m kN/m length load diagram loaded as shown M₁ M₂ maximum shearing stress midspan deflection mm² MN/m² Mohr's circle moment of inertia N/m² neutral axis obtain P₁ P₂ plane plate positive principal stresses proportional limit R₁ R₂ R2 Figure radius reaction resisting restrained beam resultant rivet segment shaft shear diagram shearing force shown in Fig simply supported beam Solution span statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld ΕΙ