Strength of Materials |
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Page 260
... acting on the beam . The effect of this transformation to symmetry is to double the actual midspan deflection . In other words , the actual midspan deflection is equal to one - half 260 6 Beam Deflections 6-7 MIDSPAN DEFLECTIONS.
... acting on the beam . The effect of this transformation to symmetry is to double the actual midspan deflection . In other words , the actual midspan deflection is equal to one - half 260 6 Beam Deflections 6-7 MIDSPAN DEFLECTIONS.
Page 261
Ferdinand Leon Singer, Andrew Pytel. the actual midspan deflection is equal to one - half the midspan deflec- tion of the transformed symmetrically loaded beam . Note that there is so little difference between midspan deflection and the ...
Ferdinand Leon Singer, Andrew Pytel. the actual midspan deflection is equal to one - half the midspan deflec- tion of the transformed symmetrically loaded beam . Note that there is so little difference between midspan deflection and the ...
Page 263
... midspan deflection of the original loading . We obtain [ EltA / B = ( area ) AB · XA ] 3 ) ( 2 × 3 ) - ( 2 x1200 ) ( 2 ) 2E18 = ( 2400 × 3 ) 3 - ( 3 x 1200 2 2 ) ... midspan deflection for the simply supported beam 6-7 Midspan Deflections 263.
... midspan deflection of the original loading . We obtain [ EltA / B = ( area ) AB · XA ] 3 ) ( 2 × 3 ) - ( 2 x1200 ) ( 2 ) 2E18 = ( 2400 × 3 ) 3 - ( 3 x 1200 2 2 ) ... midspan deflection for the simply supported beam 6-7 Midspan Deflections 263.
Common terms and phrases
allowable stresses aluminum angle applied load assumed axial load beam carrying beam in Fig beam loaded beam shown bending moment bolt bronze cantilever beam centroid column compressive stress concentrated load continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equilibrium equivalent exploratory section factor of safety fibers free-body diagram GN/m² Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS kN.m kN·m kN/m length load diagram loaded as shown M₁ M₂ maximum shearing stress midspan deflection mm² MN/m² Mohr's circle moment of inertia N/m² neutral axis obtain P₁ P₂ plane plate positive principal stresses proportional limit R₁ R₂ R2 Figure radius reaction resisting restrained beam resultant rivet segment shaft shear diagram shearing force shown in Fig simply supported beam Solution span statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld ΕΙ