## Strength of materials |

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Page 177

from the

desirable for materials that are equally strong in tension and compression.

However, for materials relatively weak in tension and strong in compression,

such as cast ...

from the

**neutral axis**—which is the centroidal axis—such beam sections aredesirable for materials that are equally strong in tension and compression.

However, for materials relatively weak in tension and strong in compression,

such as cast ...

Page 185

This analysis shows that the maximum unbalanced horizontal force exists at the

layers below the

This analysis shows that the maximum unbalanced horizontal force exists at the

**neutral axis**. This unbalanced force decreases gradually to zero as the effects oflayers below the

**neutral axis**are included. This is so because the horizontal ...Page 546

13-9 UNSYMMETRICAL BENDING The theory of flexure developed in Chapter 5

was restricted to loads lying in a plane that contained an axis of symmetry of the

cross section. With this restriction, the

...

13-9 UNSYMMETRICAL BENDING The theory of flexure developed in Chapter 5

was restricted to loads lying in a plane that contained an axis of symmetry of the

cross section. With this restriction, the

**neutral axis**passes through the centroid of...

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allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld