Strength of Materials |
From inside the book
Results 1-3 of 60
Page 77
... resisting torque T ,. The resisting torque T , is the sum of the resisting torques developed by all differential loads dP : T = T , = √ p dP = = Sp ( r dA ) Replacing 7 by its value from Eq . ( c ) gives T = G Sp2 dA GO L or , since ...
... resisting torque T ,. The resisting torque T , is the sum of the resisting torques developed by all differential loads dP : T = T , = √ p dP = = Sp ( r dA ) Replacing 7 by its value from Eq . ( c ) gives T = G Sp2 dA GO L or , since ...
Page 426
... resisting couple , composed of the equal compressive and tensile forces C and T , therefore has a moment arm jd equal to jd = d - ( kd ) ( 10-3 ) The notation for stresses in reinforced concrete differs from that used elsewhere in this ...
... resisting couple , composed of the equal compressive and tensile forces C and T , therefore has a moment arm jd equal to jd = d - ( kd ) ( 10-3 ) The notation for stresses in reinforced concrete differs from that used elsewhere in this ...
Page 574
... resisting moment at this section is Myp = bh2 бур 6 ( a ) At section b - b , the section is elastic over the depth 2y ,, but plastic outside this depth , as shown by the stress distribution in part ( c ) . The stress is constant at Oyp ...
... resisting moment at this section is Myp = bh2 бур 6 ( a ) At section b - b , the section is elastic over the depth 2y ,, but plastic outside this depth , as shown by the stress distribution in part ( c ) . The stress is constant at Oyp ...
Common terms and phrases
allowable stresses aluminum angle applied load assumed axial load beam carrying beam in Fig beam loaded beam shown bending moment bolt bronze cantilever beam centroid column compressive stress concentrated load continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equilibrium equivalent exploratory section factor of safety fibers free-body diagram GN/m² Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS kN.m kN·m kN/m length load diagram loaded as shown M₁ M₂ maximum shearing stress midspan deflection mm² MN/m² Mohr's circle moment of inertia N/m² neutral axis obtain P₁ P₂ plane plate positive principal stresses proportional limit R₁ R₂ R2 Figure radius reaction resisting restrained beam resultant rivet segment shaft shear diagram shearing force shown in Fig simply supported beam Solution span statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld ΕΙ