## Strength of materials |

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Page 127

Of almost equal importance are the following variations of Eqs. (a) and (b), which

enable us to sketch the shapes of the shear and moment diagrams: w = %:: =

Of almost equal importance are the following variations of Eqs. (a) and (b), which

enable us to sketch the shapes of the shear and moment diagrams: w = %:: =

**slope**of shear diagram (4-5) V = -% =**slope**of moment diagram (4-6) As an ...Page 132

From E to C, however, the

downward to the right as the corresponding shear ordinates change their sign to

negative. At C, the shear ordinate changes abruptly from -4 to — 12 kN, at which

it ...

From E to C, however, the

**slope**is again increasingly steeper and directeddownward to the right as the corresponding shear ordinates change their sign to

negative. At C, the shear ordinate changes abruptly from -4 to — 12 kN, at which

it ...

Page 269

loading will correspond to the actual

reason for supplying artificial constraints when solving cantilever problems

should now be clear. To produce an actual zero

cantilever, the ...

loading will correspond to the actual

**slope**and deflection at the free end. Thereason for supplying artificial constraints when solving cantilever problems

should now be clear. To produce an actual zero

**slope**at C in the originalcantilever, the ...

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### Common terms and phrases

allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld