## Strength of materials |

### From inside the book

Results 1-3 of 71

Page 35

the

the

These conditions are as follows: 1. The specimen must be of constant cross

section. 2.

the

**strain**must be constant over that length. However, under certain conditionsthe

**strain**may be assumed constant and its value computed from Eq. (2-1).These conditions are as follows: 1. The specimen must be of constant cross

section. 2.

Page 404

Since B and B' rotate in opposite directions,* their absolute sum is equal to their

algebraic difference. Hence the total change in the right angle between OA and

its normal OB, which defines the shearing

the ...

Since B and B' rotate in opposite directions,* their absolute sum is equal to their

algebraic difference. Hence the total change in the right angle between OA and

its normal OB, which defines the shearing

**strain**for an element located 0° fromthe ...

Page 405

“I 000

stress and

stress and

...

“I 000

**Strain**circle Stress circle in which R, and R, are respectively the radii of thestress and

**strain**circles in Fig. 9-27 and (OC), and (OC), are respectively thestress and

**strain**coordinates of the centers of the concentric circles. Also E is the...

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Common terms and phrases

allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld