Strength of Materials |
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Page 165
... load of 40 kN and a uniformly distributed load of 15 kN / m over its entire length , including the weight of the beam . Determine the maximum length of the beam if the flexural stress is not to exceed 140 MPa . Refer to Appendix B for ...
... load of 40 kN and a uniformly distributed load of 15 kN / m over its entire length , including the weight of the beam . Determine the maximum length of the beam if the flexural stress is not to exceed 140 MPa . Refer to Appendix B for ...
Page 234
... uniformly distributed load included between B and b - b . Note that defining the bending moment in terms of the forces to the left of the section means that the uniformly distributed load has no moment effect on segment AB . Actually ...
... uniformly distributed load included between B and b - b . Note that defining the bending moment in terms of the forces to the left of the section means that the uniformly distributed load has no moment effect on segment AB . Actually ...
Page 327
... uniformly distributed load of w N / m over the middle span . Ans . M2 M3 = - wL2 4 wL2 = 4 1 + 2B 4 ( 1 + a ) ( 1 + ... load of 2 kN at the center of the first span , a concentrated load of 3 kN at the center of the third span , and a ...
... uniformly distributed load of w N / m over the middle span . Ans . M2 M3 = - wL2 4 wL2 = 4 1 + 2B 4 ( 1 + a ) ( 1 + ... load of 2 kN at the center of the first span , a concentrated load of 3 kN at the center of the third span , and a ...
Common terms and phrases
allowable stresses aluminum angle applied load assumed axial load beam carrying beam in Fig beam loaded beam shown bending moment bolt bronze cantilever beam centroid column compressive stress concentrated load continuous beam cross section deformation Determine the maximum diameter elastic curve end moments equal equilibrium equivalent exploratory section factor of safety fibers free-body diagram GN/m² Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS kN.m kN·m kN/m length load diagram loaded as shown M₁ M₂ maximum shearing stress midspan deflection mm² MN/m² Mohr's circle moment of inertia N/m² neutral axis obtain P₁ P₂ plane plate positive principal stresses proportional limit R₁ R₂ R2 Figure radius reaction resisting restrained beam resultant rivet segment shaft shear diagram shearing force shown in Fig simply supported beam Solution span statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load vertical shear weld ΕΙ