## Strength of materials |

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Page 256

Compute the midspan

the M diagram by parts, starting from midspan toward the ends. Also take

advantage of symmetry to note that the tangent drawn to the elastic curve at

midspan is ...

Compute the midspan

**value of E18**for the beam shown in Fig. P-653. (Hint: Drawthe M diagram by parts, starting from midspan toward the ends. Also take

advantage of symmetry to note that the tangent drawn to the elastic curve at

midspan is ...

Page 344

Compute the

shown in Fig. P--865, compute the value of E16 at x = 3 m and at the end of the

overhang. Ans. At overhang, E18 = 813 N - ma down 800 N/m 400 N/m \ 3m lmt

2m R1 ...

Compute the

**value of E18**at the middle and at the ends. 865. For the beamshown in Fig. P--865, compute the value of E16 at x = 3 m and at the end of the

overhang. Ans. At overhang, E18 = 813 N - ma down 800 N/m 400 N/m \ 3m lmt

2m R1 ...

Page 345

Determine the

shown in Fig. P-868. Ans. At ends, E18 = 10.9 kN - ma up R1 R2 Figure P-868. Z

x\ a/B 869. Find the

Determine the

**values of E18**at midspan and at the ends of the beam loaded asshown in Fig. P-868. Ans. At ends, E18 = 10.9 kN - ma up R1 R2 Figure P-868. Z

x\ a/B 869. Find the

**value of E18**at the center of the first span of the continuous ...### What people are saying - Write a review

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### Common terms and phrases

allowable stresses aluminum angle applied load area-moment method assumed axial load beam in Fig beam loaded beam shown bolt bronze cantilever beam caused centroid column compressive stress concentrated load continuous beam cross section deﬂection deformation Determine the maximum diameter elastic curve element end moments equal equilibrium equivalent exploratory section factor of safety fibers ﬂexural flexural stress Flgure free-body diagram Hence horizontal ILLUSTRATIVE PROBLEMS kN-m kN/m length loaded as shown maximum shearing stress maximum stress midspan midspan deﬂection Mohr’s circle neutral axis normal stress obtain plane positive principal stresses proportional limit radius reaction resisting restrained beam resultant rivet segment shaft shear center shear diagram shearing force shearing strain shown in Fig simply supported beam slope Solution span static equilibrium statically indeterminate steel strain tangent drawn tensile stress three-moment equation torque torsional uniformly distributed load value of E18 vertical shear weld