Engineering Mechanics of Materials4. 2 Solid Circular Shafts-Angle of Twist and Shearing Stresses 159 4. 3 Hollow Circular Shafts-Angle of Twist and Shearing Stresses 166 4. 4 Principal Stresses and Strains Associated with Torsion 173 4. 5 Analytical and Experimental Solutions for Torsion of Members of Noncircular Cross Sections 179 4. 6 Shearing Stress-Strain Properties 188 *4. 7 Computer Applications 195 5 Stresses in Beams 198 5. 1 Introduction 198 5. 2 Review of Properties of Areas 198 5. 3 Flexural Stresses due to Symmetric Bending of Beams 211 5. 4 Shear Stresses in Symmetrically Loaded Beams 230 *5. 5 Flexural Stresses due to Unsymmetric Bending of Beams 248 *5. 6 Computer Applications 258 Deflections of Beams 265 I 6. 1 Introduction 265 6. 2 Moment-Curvature Relationship 266 6. 3 Beam Deflections-Two Successive Integrations 268 6. 4 Derivatives of the Elastic Curve Equation and Their Physical Significance 280 6. 5 Beam Deflections-The Method of Superposition 290 6. 6 Construction of Moment Diagrams by Cantilever Parts 299 6. 7 Beam Deflections-The Area-Moment Method 302 *6. 8 Beam Deflections-Singularity Functions 319 *6. 9 Beam Deflections-Castigliano's Second Theorem 324 *6. 10 Computer Applications 332 7 Combined Stresses and Theories of Failure 336 7. 1 Introduction 336 7. 2 Axial and Torsional Stresses 336 Axial and Flexural Stresses 342 7. 3 Torsional and Flexural Stresses 352 7. 4 7. 5 Torsional, Flexural, and Axial Stresses 358 *7. 6 Theories of Failure 365 Computer Applications 378 *7. |
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Page 153
... modulus of elasticity 30 × 10 psi , and its Poisson's ratio is 0.30 . Determine : ( a ) The maximum compressive load that may be applied without exceeding the proportional limit . ( b ) The changes in diameter and in length at the pro ...
... modulus of elasticity 30 × 10 psi , and its Poisson's ratio is 0.30 . Determine : ( a ) The maximum compressive load that may be applied without exceeding the proportional limit . ( b ) The changes in diameter and in length at the pro ...
Page 193
... modulus of elasticity . ( c ) The modulus of resilience . T ( kN⚫m ) 66.85 1.00 174.0 18.0 80.22 1.20 176.0 20.0 93.58 1.40 177.0 22.0 106.9 1.60 178.0 24.0 125.0 1.87 180.0 26.0 138.0 3.00 181.0 28.0 144.0 4.00 182.0 30.0 30.0 150.0 ...
... modulus of elasticity . ( c ) The modulus of resilience . T ( kN⚫m ) 66.85 1.00 174.0 18.0 80.22 1.20 176.0 20.0 93.58 1.40 177.0 22.0 106.9 1.60 178.0 24.0 125.0 1.87 180.0 26.0 138.0 3.00 181.0 28.0 144.0 4.00 182.0 30.0 30.0 150.0 ...
Page 194
... modulus of elasticity . ( b ) Find the equation of the shearing stress - strain line below the yield point . ( c ) Plot the stress - strain diagram for shear . ( d ) Find the modulus of resilience . Circular cylindrical specimen : 4.54 ...
... modulus of elasticity . ( b ) Find the equation of the shearing stress - strain line below the yield point . ( c ) Plot the stress - strain diagram for shear . ( d ) Find the modulus of resilience . Circular cylindrical specimen : 4.54 ...
Contents
Stresses in Beams | 198 |
Deflections of Beams | 265 |
Combined Stresses and Theories of Failure | 336 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive constant coordinate cross section cross-sectional area cylinder deflection deformation depicted in Fig diameter elastic curve equal equation equilibrium Euler EXAMPLE factor of safety FIGURE flexural stress FORTRAN free-body diagram k-ft k-in kN-m lb/ft length longitudinal M₁ material maximum shear stress modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plane stress condition plot principal centroidal axis principal stresses r₁ radius ratio rectangular Refer to Fig rotation shaft shear force shear strain shown in Fig slope SOLUTION statically indeterminate steel stress element T₁ t₂ tensile Tmax torque torsional uniform load V₁ yield stress zero