## Engineering mechanics of materialsThis book provides the students of various engineering disciplines with a clear and understandable treatment of the concepts of Mechanics of Materials or Strength of Materials. This subject is concerned with the behavior of deformable bodies when subjected to axial, torsional and flexural loads as well as combinations thereof. It is a 3rd, updated edition of the popular undergraduate level textbook useful for students of mechanical, structural, civil, aeronautical and other engineering disciplines. The book is supplied with problems and a solution manual will be available from the authors. |

### From inside the book

Results 1-3 of 83

Page 486

Consider, for example, the way properties of materials are

laboratory. As discussed in Section 3.4, small samples (specimens) are prepared

from a given material, and it is assumed that the average properties

from the ...

Consider, for example, the way properties of materials are

**obtained**in thelaboratory. As discussed in Section 3.4, small samples (specimens) are prepared

from a given material, and it is assumed that the average properties

**obtained**from the ...

Page 592

This free-body diagram was

with a cutting y-z plane, and then isolating a small segment from one of the two

halves, contained between two cutting planes perpendicular to the cylinder axis

at ...

This free-body diagram was

**obtained**by first slicing the cylinder into two halveswith a cutting y-z plane, and then isolating a small segment from one of the two

halves, contained between two cutting planes perpendicular to the cylinder axis

at ...

Page 622

Using the flexure equation, we can

follows: _MJi 60,000 x 4 6250 psi The maximum flexural stress in the oak is now

Using the flexure equation, we can

**obtain**the flexural stress in the aluminum asfollows: _MJi 60,000 x 4 6250 psi The maximum flexural stress in the oak is now

**obtained**from Eq. 13.24. Thus KaJmax = "KlLax = 3(6250) 1250 psi The same ...### What people are saying - Write a review

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### Contents

Stress Strain and Their Relationships | 60 |

Stresses and Strains in Axially Loaded Members | 121 |

Torsional Stresses Strains and Rotations | 159 |

Copyright | |

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### Common terms and phrases

absolute maximum shear aluminum angle of twist applied Assume axial force axially loaded beam shown bending cantilever beam Castigliano's second theorem column compressive constant coordinate cross section cross-sectional area cylinder deflection deformation depicted in Fig elastic curve equal equation equilibrium Euler EXAMPLE factor of safety FIGURE flexural stress FORTRAN free-body diagram function given by Eq k-ft k-in kN-m lb/ft length longitudinal material maximum in-plane shear maximum shear stress modulus of elasticity Mohr's circle neutral axis normal stress obtained perpendicular plane stress condition plot positive principal centroidal axis principal strains principal stresses radius ratio reactions Refer to Fig respect rotation shear force shear strain shown in Fig simply supported beam slope SOLUTION Solve Problem statically indeterminate steel stress concentration stress element subjected torque torsional uniform load vertical yield strength yield stress zero