## The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth |

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Page 7

A , B ;

A , B ;

**ABC**shall be an equilateral**triangle**. Because the point A is the centre of the circle BCD , AC is equal * to AB ; and because the point B is the * 15 Deficentre of the circle ACE , BC is equal to BA : but it has nition . been ... Page 8

Let ABC , DEF be two triangles , which have the two sides AB , AC equal to the two sides DE , DF , each to each , viz . ... and the

Let ABC , DEF be two triangles , which have the two sides AB , AC equal to the two sides DE , DF , each to each , viz . ... and the

**triangle ABC**to the triangle DEF ; and the other angles А CE to which the equal sides are opposite ... Page 9

to which the equal sides are opposite , shall be equal each to each , viz . the angle ABC to the angle DEF , and the angle ACB to DFE . For , if the

to which the equal sides are opposite , shall be equal each to each , viz . the angle ABC to the angle DEF , and the angle ACB to DFE . For , if the

**triangle ABC**be applied to DEF , so that the point A may be on D , and the straight ... Page 10

FA G IE * 3 Ax . the two

FA G IE * 3 Ax . the two

**triangles**AFC , AGB ; therefore the base FC is equal * to the base GB , and the**triangle**AFC to ... Let**ABC**be a**triangle**having the angle**ABC**equal to the angle ACB : the side AB shall be equal to the side AC . Page 12

For , if the

For , if the

**triangle ABC**be applied to DEF , so that the point B may be on E , and the straight line BC upon EF ; the point C shall also coincide with the point F , because BC is equal † to EF . Therefore BC coinciding with EF , BA and ...### What people are saying - Write a review

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The Elements of Euclid: Viz. The First Six Books, Together With the Eleventh ... Euclid Euclid No preview available - 2018 |

### Common terms and phrases

added altitude angle ABC angle BAC base Book centre circle circle ABCD circumference common cone contained cylinder definition demonstrated described diameter difference divided double draw drawn equal equal angles equiangular equimultiples Euclid excess figure fore four fourth given angle given in position given in species given magnitude given ratio given straight line greater Greek half join less likewise logarithm magnitude manner meet multiple opposite parallel parallelogram pass perpendicular plane prism produced PROP proportionals proposition proved pyramid radius reason rectangle rectilineal figure remaining right angles segment shewn sides similar sine solid sphere square square of AC taken THEOR third triangle ABC wherefore whole