Strength of Materials |
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Page 394
... Euler's formula to be applicable , the stress accompanying the bending which occurs during buckling must not exceed the proportional limit . This stress may be found by replacing in Euler's formula the mo- ment of inertia I by its ...
... Euler's formula to be applicable , the stress accompanying the bending which occurs during buckling must not exceed the proportional limit . This stress may be found by replacing in Euler's formula the mo- ment of inertia I by its ...
Page 395
... ( 30 × 106 ) π2 - 70.7 in . 1 L Also , the slenderness ratio 100 , from which the least k is k L 22 X 12 k ≤ = 2.64 in . 100 100 These criteria establish that the section must have a least Art . 11-4 ] 395 Limitations of Euler's Formula.
... ( 30 × 106 ) π2 - 70.7 in . 1 L Also , the slenderness ratio 100 , from which the least k is k L 22 X 12 k ≤ = 2.64 in . 100 100 These criteria establish that the section must have a least Art . 11-4 ] 395 Limitations of Euler's Formula.
Page 396
... Euler's formula is based . This problem demonstrates the importance of the slenderness ratio in column analysis . In part ( a ) the selection is governed by elastic stability ( i.e. , the use of Euler's formula ) , whereas in part ( b ) ...
... Euler's formula is based . This problem demonstrates the importance of the slenderness ratio in column analysis . In part ( a ) the selection is governed by elastic stability ( i.e. , the use of Euler's formula ) , whereas in part ( b ) ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ