Strength of Materials |
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Page 283
... Solve Prob . 819 if the concentrated load is replaced by a uniformly distributed load of w lb / ft over the first span . Ans . M2 = WL2 2 ( a + B ) 4 4 ( 1 + a ) ( a + B ) a2 wL2 α M3 = + 4 4 ( 1 + α ) ( a + B ) a2 821. See Fig . 821 ...
... Solve Prob . 819 if the concentrated load is replaced by a uniformly distributed load of w lb / ft over the first span . Ans . M2 = WL2 2 ( a + B ) 4 4 ( 1 + a ) ( a + B ) a2 wL2 α M3 = + 4 4 ( 1 + α ) ( a + B ) a2 821. See Fig . 821 ...
Page 338
Ferdinand Leon Singer. 937. Solve Prob . 936 if the directions of the 4000 psi shearing stresses in ( b ) are reversed . Can you anticipate whether the results will be changed ? 938. Solve Prob . 936 if the N axis is changed in ( b ) so ...
Ferdinand Leon Singer. 937. Solve Prob . 936 if the directions of the 4000 psi shearing stresses in ( b ) are reversed . Can you anticipate whether the results will be changed ? 938. Solve Prob . 936 if the N axis is changed in ( b ) so ...
Page 376
... Solve Prob . 1031 if the bending moment is 50,000 ft - lb , all other data remaining unchanged . 1033. Solve Prob . 1027 by computing the moment of inertia of the trans- formed section , and then applying the flexure formula according ...
... Solve Prob . 1031 if the bending moment is 50,000 ft - lb , all other data remaining unchanged . 1033. Solve Prob . 1027 by computing the moment of inertia of the trans- formed section , and then applying the flexure formula according ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ