Strength of Materials |
From inside the book
Results 1-3 of 83
Page 70
... applied at B. 315. A 16 - ft shaft rotating at 126 rpm has 100 hp applied at a gear that is 6 ft from the left end where 30 hp are removed . At the right end , 40 hp are removed and another 30 hp leaves the shaft at 5 ft from the right ...
... applied at B. 315. A 16 - ft shaft rotating at 126 rpm has 100 hp applied at a gear that is 6 ft from the left end where 30 hp are removed . At the right end , 40 hp are removed and another 30 hp leaves the shaft at 5 ft from the right ...
Page 462
... applied to ductile ma- terials . For such materials the maximum shear theory also gives good agreement . For rupture in brittle materials , such as cast iron , the maximum stress theory is generally preferred . 13-5 . Energy Methods By ...
... applied to ductile ma- terials . For such materials the maximum shear theory also gives good agreement . For rupture in brittle materials , such as cast iron , the maximum stress theory is generally preferred . 13-5 . Energy Methods By ...
Page 523
... applied and then removed , determine the residual Pa - 8100 lb ; P , = 16,200 lb If a load P = force in each bar ... applied at P and then removed . -10 ′′ - + 15 " Aluminum E = 10 × 106 P Steel E = 30 × 106 A = 1.5 in.2 A = 2 in.2 2 " 2 ...
... applied and then removed , determine the residual Pa - 8100 lb ; P , = 16,200 lb If a load P = force in each bar ... applied at P and then removed . -10 ′′ - + 15 " Aluminum E = 10 × 106 P Steel E = 30 × 106 A = 1.5 in.2 A = 2 in.2 2 " 2 ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
26 other sections not shown
Other editions - View all
Common terms and phrases
acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ