Strength of Materials |
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Page 553
... axes , marked X ' and Y ' and rotated 90 ° counterclockwise from the original set of axes , the area is in the fourth quadrant . The new coordinates of dA are x'y and y ' with respect to the new axes , the product of inertia is Px'y ...
... axes , marked X ' and Y ' and rotated 90 ° counterclockwise from the original set of axes , the area is in the fourth quadrant . The new coordinates of dA are x'y and y ' with respect to the new axes , the product of inertia is Px'y ...
Page 561
... axes passing through a specified point in an area . For convenience , the rules in Art . 9-7 are rephrased as follows to apply to moments of inertia : 1. On a set of rectangular coordinate axes , choose one axis on which to plot ...
... axes passing through a specified point in an area . For convenience , the rules in Art . 9-7 are rephrased as follows to apply to moments of inertia : 1. On a set of rectangular coordinate axes , choose one axis on which to plot ...
Page 563
... axes which have a zero product of inertia must be axes of maximum or minimum inertia . Such axes are called principal axes . As we have already seen ( Art . A - 8 ) , the products of inertia relative to axes of symmetry are zero . Hence ...
... axes which have a zero product of inertia must be axes of maximum or minimum inertia . Such axes are called principal axes . As we have already seen ( Art . A - 8 ) , the products of inertia relative to axes of symmetry are zero . Hence ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ