## Strength of Materials |

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Page 100

—3480 ft-lb 405.

Br B 200 lb/ ft ID 300 lb/ ft 400 lb/ ft 6' 4' A 3' 6' 6' I I Fig. P-405. 406.

...

**Beam loaded**as shown in Fig. P-404. Ans. MBc = 3600 - 230a; - 30z2; Max. M =—3480 ft-lb 405.

**Beam loaded**as shown in Fig. P-405. Ans. Max. M = 3456 ft-lbBr B 200 lb/ ft ID 300 lb/ ft 400 lb/ ft 6' 4' A 3' 6' 6' I I Fig. P-405. 406.

**Beam loaded**...

Page 119

P-444. Fig. P-445. 446.

carrying the triangular load shown in Fig. P-447 is supported on a uniformly

distributed reaction. Ans. Max. M = 7200 ft-lb , ^-240 lb /ft Fig. P-446. Fig. P-447

and P-448.

P-444. Fig. P-445. 446.

**Beam loaded**as shown in Fig. P-446. 447. A beamcarrying the triangular load shown in Fig. P-447 is supported on a uniformly

distributed reaction. Ans. Max. M = 7200 ft-lb , ^-240 lb /ft Fig. P-446. Fig. P-447

and P-448.

Page 207

Ferdinand Leon Singer. PROBLEMS For each of the beams in the following

problems, compute the moment of area of the M diagram between the reactions

about both the left and the right reaction. 624.

624.

Ferdinand Leon Singer. PROBLEMS For each of the beams in the following

problems, compute the moment of area of the M diagram between the reactions

about both the left and the right reaction. 624.

**Beam loaded**as shown in Fig. P-624.

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