Strength of Materials |
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Page 31
... deformation 8 , the ap- plied load P , the length L , the cross - sectional area A , and the modulus of elasticity E. The unit of deformation & has the same unit as length L ... deformation . is Art . 2-3 ] 31 Hooke's Law . Axial Deformation.
... deformation 8 , the ap- plied load P , the length L , the cross - sectional area A , and the modulus of elasticity E. The unit of deformation & has the same unit as length L ... deformation . is Art . 2-3 ] 31 Hooke's Law . Axial Deformation.
Page 62
... deformation 8 . equal to DE . The length of this deformation is the arc of a circle whose radius is p and which is subtended by the angle of radians ; the length is given by 88 - DE = ρθ The unit deformation of this fiber is Y = δε L ρθ ...
... deformation 8 . equal to DE . The length of this deformation is the arc of a circle whose radius is p and which is subtended by the angle of radians ; the length is given by 88 - DE = ρθ The unit deformation of this fiber is Y = δε L ρθ ...
Page 67
... deformation , so that 00. Applying Eq . ( 3–1 ) = 2 ) . gives ( CA ) . - ( 74 ) . ] T. ( 3 ) ' Ta ( 6 ) π ( 2 ) 4 ... deformation is the algebraic sum of the deformation in each segment . Arbitrarily denoting clockwise deformation as ...
... deformation , so that 00. Applying Eq . ( 3–1 ) = 2 ) . gives ( CA ) . - ( 74 ) . ] T. ( 3 ) ' Ta ( 6 ) π ( 2 ) 4 ... deformation is the algebraic sum of the deformation in each segment . Arbitrarily denoting clockwise deformation as ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ