Strength of Materials |
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Page 160
... flange . Neglect the weakening effect of the rivet holes . Ans . ( a ) 136,000 lb ; ( b ) 120,000 lb = 561. A T ... flange is 1000 psi , calculate ( a ) the total tensile force in the flange and ( b ) the total compressive force in the ...
... flange . Neglect the weakening effect of the rivet holes . Ans . ( a ) 136,000 lb ; ( b ) 120,000 lb = 561. A T ... flange is 1000 psi , calculate ( a ) the total tensile force in the flange and ( b ) the total compressive force in the ...
Page 477
... flange and compression in the lower flange , therefore , the shearing stresses in these flanges point in opposite directions . The magnitude of the longitudinal shearing stress across the flange is given by Eq . ( 5-4 ) ( page 163 ) if ...
... flange and compression in the lower flange , therefore , the shearing stresses in these flanges point in opposite directions . The magnitude of the longitudinal shearing stress across the flange is given by Eq . ( 5-4 ) ( page 163 ) if ...
Page 482
... flange that has the larger moment of inertia . When there is only one flange , as in the T section in Fig . 13-23 , if the bending resistance of the web is again assumed to be negligible , the shear center coincides with the centroid of ...
... flange that has the larger moment of inertia . When there is only one flange , as in the T section in Fig . 13-23 , if the bending resistance of the web is again assumed to be negligible , the shear center coincides with the centroid of ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ