Strength of Materials |
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Page 168
... shearing stress is = [ S. - [ 47 ] V A'y Ib Ss = 1800 72 ( 4 ) ( 4 X 3 ) ( 1.5 ) = 112.5 psi If desired , Eq . ( 5-6 ) may be used . As noted on page 165 , this equation determines the maximum shearing stress on any rectangular section ...
... shearing stress is = [ S. - [ 47 ] V A'y Ib Ss = 1800 72 ( 4 ) ( 4 X 3 ) ( 1.5 ) = 112.5 psi If desired , Eq . ( 5-6 ) may be used . As noted on page 165 , this equation determines the maximum shearing stress on any rectangular section ...
Page 170
... shearing stress in the web will be very close to the maximum shearing stress as computed from Eq . ( 5-4 ) . Thus = [ s . - 1 ] V A web S. = 16,000 10 X 1 = 1600 psi This is very close to the computed maximum , 1590 psi . This method ...
... shearing stress in the web will be very close to the maximum shearing stress as computed from Eq . ( 5-4 ) . Thus = [ s . - 1 ] V A web S. = 16,000 10 X 1 = 1600 psi This is very close to the computed maximum , 1590 psi . This method ...
Page 461
Ferdinand Leon Singer. This indicates that the maximum tensile or compressive stress alone is not sufficient to ... shearing stress equals the maximum shearing stress developed at yielding in simple tension . Since the maximum shearing ...
Ferdinand Leon Singer. This indicates that the maximum tensile or compressive stress alone is not sufficient to ... shearing stress equals the maximum shearing stress developed at yielding in simple tension . Since the maximum shearing ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ