Strength of Materials |
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Page 145
... modulus of 30 in.3 will require changing the original selection to a 14 WF 30 beam . TABLE 5-2 . Beam Economy Section Concrete d Section Concrete Modulus Shape ( lb / ft ) bt Modulus Shape ( lb / ft ) 813 d bt 1105.1 36 WF 300 830 1.31 ...
... modulus of 30 in.3 will require changing the original selection to a 14 WF 30 beam . TABLE 5-2 . Beam Economy Section Concrete d Section Concrete Modulus Shape ( lb / ft ) bt Modulus Shape ( lb / ft ) 813 d bt 1105.1 36 WF 300 830 1.31 ...
Page 146
... modulus . In addition to section modulus and shape , the table lists the weight of a concrete encasement d in lb / ft , and the product for checking lateral deflection when necessary . The bt table is a modification of a similar table ...
... modulus . In addition to section modulus and shape , the table lists the weight of a concrete encasement d in lb / ft , and the product for checking lateral deflection when necessary . The bt table is a modification of a similar table ...
Page 398
... modulus curve Euler's curve P = ET2 A ( 4 ) 2 Long columns 200 k their departure from the stress - strain ... modulus theory * -the Euler formula is extended to intermediate columns stressed above the pro- portional limit by replacing ...
... modulus curve Euler's curve P = ET2 A ( 4 ) 2 Long columns 200 k their departure from the stress - strain ... modulus theory * -the Euler formula is extended to intermediate columns stressed above the pro- portional limit by replacing ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ