Strength of Materials |
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Page 152
... neutral axis . With such a cross section , the stronger fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the cen- troidal or neutral axis in ...
... neutral axis . With such a cross section , the stronger fibers can be located at a greater distance from the neutral axis than the weaker fibers . The ideal treatment for such materials is to locate the cen- troidal or neutral axis in ...
Page 160
... neutral axis . This unbalanced force decreases gradually to zero as the effects of layers below the neutral axis are included . This is so because the horizontal effect of the compressive forces is increasingly offset by the ...
... neutral axis . This unbalanced force decreases gradually to zero as the effects of layers below the neutral axis are included . This is so because the horizontal effect of the compressive forces is increasingly offset by the ...
Page 488
... axis is the neutral axis , whereas in ( c ) the Y axis becomes the neutral axis . Each of these conditions produces flexure stresses that are normal to the cross section ; hence the resultant stress at any point is the algebraic sum of ...
... axis is the neutral axis , whereas in ( c ) the Y axis becomes the neutral axis . Each of these conditions produces flexure stresses that are normal to the cross section ; hence the resultant stress at any point is the algebraic sum of ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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Common terms and phrases
acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ