Strength of Materials |
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Page 163
... stress over the differential area of width b and length dr ; also that M2 M1 represents the differential change in bending moment dM in the distance dx ; hence ... stress Art . 5-7 ] Derivation of Formula for Horizontal Shearing Stress 163.
... stress over the differential area of width b and length dr ; also that M2 M1 represents the differential change in bending moment dM in the distance dx ; hence ... stress Art . 5-7 ] Derivation of Formula for Horizontal Shearing Stress 163.
Page 327
... shearing stress is denoted by a double subscript , the first letter correspond- ing to the face on which the shearing stress acts and the second indicating the direction in which it acts . Thus the shearing stress on the X face act- ing ...
... shearing stress is denoted by a double subscript , the first letter correspond- ing to the face on which the shearing stress acts and the second indicating the direction in which it acts . Thus the shearing stress on the X face act- ing ...
Page 341
... shearing stress S 12,000 psi or a resultant normal stress Sp = 16,000 psi . = Solution : The bending moment produces a maximum flexural stress at the top or bottom of the shaft . Its value is Mc S = [ s , - ME - AM ] I S = 4 ( 2000 X 12 ) ...
... shearing stress S 12,000 psi or a resultant normal stress Sp = 16,000 psi . = Solution : The bending moment produces a maximum flexural stress at the top or bottom of the shaft . Its value is Mc S = [ s , - ME - AM ] I S = 4 ( 2000 X 12 ) ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ