## Strength of Materials |

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Page 125

A comparison of the above results shows that the most dangerous bending

moment is 64.0 ton-ft, occurring under C when only loads B and C are on the

load R is ...

A comparison of the above results shows that the most dangerous bending

moment is 64.0 ton-ft, occurring under C when only loads B and C are on the

**span**. Maximum Shearing Force. If all three loads are on the**span**, the resultantload R is ...

Page 275

resulting from carrying the applied loads on a simple

the equivalent beam segment. The general expressions in Table 8-1 were

obtained by the following procedure. (a) Load on simple

diagram Fig.

resulting from carrying the applied loads on a simple

**span**of the same length asthe equivalent beam segment. The general expressions in Table 8-1 were

obtained by the following procedure. (a) Load on simple

**span**(b) Momentdiagram Fig.

Page 284

distributed load of w lb/ft over the middle

(1 + a)(a + 0) - 1 1 + 2a 4(1 + a) (a + 18) - 1 823. A continuous beam simply

supported over three 10-ft

center of ...

distributed load of w lb/ft over the middle

**span**. Am. M2 = M3 = wL wL2 4 1 + 20 4(1 + a)(a + 0) - 1 1 + 2a 4(1 + a) (a + 18) - 1 823. A continuous beam simply

supported over three 10-ft

**spans**carries a concentrated load of 400 lb at thecenter of ...

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allowable stresses aluminum angle assumed axes axial load beam loaded beam shown bending bending moment bolt cantilever beam caused centroid CN CN CN column compressive stress Compute the maximum concentrated load concrete cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan modulus Mohr's circle moment of area moment of inertia moments of inertia neutral axis obtain plane plastic product of inertia proportional limit radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero