## Strength of Materials |

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Page 62

Slice (2) will rotate past slice (1) until the elastic fibers joining them are deformed

enough to create a resisting

happens, slices (1) and (2) will act as a rigid unit and transmit the

Slice (2) will rotate past slice (1) until the elastic fibers joining them are deformed

enough to create a resisting

**torque**which balances the applied**torque**. When thishappens, slices (1) and (2) will act as a rigid unit and transmit the

**torque**to ...Page 70

-diameter at one end to a 1-in. diameter at the other end. Assuming that no

significant discontinuity results from applying Eq. (3-1) over each infinitesimal

length, compute the angular twist when transmitting a

12 X 106 ...

-diameter at one end to a 1-in. diameter at the other end. Assuming that no

significant discontinuity results from applying Eq. (3-1) over each infinitesimal

length, compute the angular twist when transmitting a

**torque**of 1500 in.-lb. G =12 X 106 ...

Page 71

322 A

ends. Prove that the resisting

How would these values be changed if the shaft were hollow? T. 8 Fig. P-322.

323.

322 A

**torque**T is applied, as shown in Fig. P-322, to a solid shaft with Tb built-inends. Prove that the resisting

**torques**at the walls are Ti = - — and L T2 = Ta LHow would these values be changed if the shaft were hollow? T. 8 Fig. P-322.

323.

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allowable stresses aluminum angle assumed axes axial load beam loaded beam shown bending bending moment bolt cantilever beam caused centroid CN CN CN column compressive stress Compute the maximum concentrated load concrete cross section deformation Determine the maximum diameter elastic curve end moments equal equivalent Euler's formula factor of safety fibers flange flexure formula free-body diagram ft long ft-lb Hence Hooke's law horizontal ILLUSTRATIVE PROBLEMS lb/ft length loaded as shown main plate maximum shearing stress maximum stress midspan modulus Mohr's circle moment of area moment of inertia moments of inertia neutral axis obtain plane plastic product of inertia proportional limit radius reaction Repeat Prob resisting restrained beam resultant segment shaft shear center shear diagram shearing force shown in Fig Solution Solve Prob span static steel strain tensile stress thickness torque torsional uniformly distributed load vertical shear weld zero