Strength of Materials |
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Page 90
... Distributed loads may also be uniformly varying or non- uniform . In a uniformly varying or triangular load , the intensity of load- ing increases or decreases at a constant rate , as in Fig . 4-2a and 4-2b ; this condition might result ...
... Distributed loads may also be uniformly varying or non- uniform . In a uniformly varying or triangular load , the intensity of load- ing increases or decreases at a constant rate , as in Fig . 4-2a and 4-2b ; this condition might result ...
Page 201
... load is some variation of the equation y = kx " . This table gives data on four cantilever beams , each loaded ... uniformly distributed load of 30 lb / ft over the right 6 ft of the span . At any section a - a between A and B , the ...
... load is some variation of the equation y = kx " . This table gives data on four cantilever beams , each loaded ... uniformly distributed load of 30 lb / ft over the right 6 ft of the span . At any section a - a between A and B , the ...
Page 284
... load of 400 lb at the center of the first span , a concentrated load of 640 lb at the center of the third span , and a uniformly distributed load of 80 lb / ft over the middle span . Solve for the moments over the supports and check ...
... load of 400 lb at the center of the first span , a concentrated load of 640 lb at the center of the third span , and a uniformly distributed load of 80 lb / ft over the middle span . Solve for the moments over the supports and check ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ