Strength of Materials |
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Page 91
... vertical unbalance ( which is equal but oppositely directed to the resisting shearing force ) would be found from the summation of their vertical components . We define this net vertical unbalance as the shearing force in the beam . It ...
... vertical unbalance ( which is equal but oppositely directed to the resisting shearing force ) would be found from the summation of their vertical components . We define this net vertical unbalance as the shearing force in the beam . It ...
Page 163
... vertical shear ; so we obtain for V y dA = A'y Ib 1 Ib We have replaced the integral = V Q Ib ( 5-4 ) y dA , which ... Vertical Shearing Stresses . Most stu- dents are surprised to find the term vertical shear ( V ) appearing in the for ...
... vertical shear ; so we obtain for V y dA = A'y Ib 1 Ib We have replaced the integral = V Q Ib ( 5-4 ) y dA , which ... Vertical Shearing Stresses . Most stu- dents are surprised to find the term vertical shear ( V ) appearing in the for ...
Page 469
... vertical plane as shown in Fig . P - 1306 . Compute the horizontal and vertical displacements of point A. 1307. A circular bar is bent into the shape of a half - ring and supported in a vertical plane as shown in Fig . P - 1307 ...
... vertical plane as shown in Fig . P - 1306 . Compute the horizontal and vertical displacements of point A. 1307. A circular bar is bent into the shape of a half - ring and supported in a vertical plane as shown in Fig . P - 1307 ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ