Strength of Materials |
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Page 91
... shearing force . For the loading shown , V , is numerically equal to R1 ; but if additional loads had been applied between R1 and sec- tion a - a ( as in Figs . 4-5 and 4-6 ) , the net vertical unbalance ( which is equal but oppositely ...
... shearing force . For the loading shown , V , is numerically equal to R1 ; but if additional loads had been applied between R1 and sec- tion a - a ( as in Figs . 4-5 and 4-6 ) , the net vertical unbalance ( which is equal but oppositely ...
Page 163
... shearing stress , S1 = V dM dx C dM Ib dr = S y dA 71 V , the vertical shear ; so we obtain for V y dA = A'y Ib 1 Ib We have replaced the integral = V Q Ib ( 5-4 ) y dA , which means the sum of the mo- ments of the differential areas dA ...
... shearing stress , S1 = V dM dx C dM Ib dr = S y dA 71 V , the vertical shear ; so we obtain for V y dA = A'y Ib 1 Ib We have replaced the integral = V Q Ib ( 5-4 ) y dA , which means the sum of the mo- ments of the differential areas dA ...
Page 164
Ferdinand Leon Singer. vertical shearing stress . It is this vertical shearing stress S . ,, shown in Fig . 5-23 , that forms the resisting vertical shear V , Z Fig . 5-23 . Ssh Ssu dy y N.A. X V1 = √S , dA Horizontal and ver- tical ...
Ferdinand Leon Singer. vertical shearing stress . It is this vertical shearing stress S . ,, shown in Fig . 5-23 , that forms the resisting vertical shear V , Z Fig . 5-23 . Ssh Ssu dy y N.A. X V1 = √S , dA Horizontal and ver- tical ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ