Strength of Materials |
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Page 143
... weight of beam . ) The selection of the beam is not complete until a check calculation is made that includes the weight of the beam . * The beam's resisting moment MB must be equal to or greater than the sum of the live load moment ML ...
... weight of beam . ) The selection of the beam is not complete until a check calculation is made that includes the weight of the beam . * The beam's resisting moment MB must be equal to or greater than the sum of the live load moment ML ...
Page 144
... weight of beam . ) definition of bending moment , M = ( M ) R , we have MD = 270 ( 5 ) ( 27 × 5 ) ( § ) - or , from the shaded area of the shear diagram , = 1013 ft - lb MD = ( 270 +135 ) 2 ( 5 ) = 1013 ft - lb Therefore , the section ...
... weight of beam . ) definition of bending moment , M = ( M ) R , we have MD = 270 ( 5 ) ( 27 × 5 ) ( § ) - or , from the shaded area of the shear diagram , = 1013 ft - lb MD = ( 270 +135 ) 2 ( 5 ) = 1013 ft - lb Therefore , the section ...
Page 146
... weight of a concrete encasement d in lb / ft , and the product for checking lateral deflection when necessary . The bt table is a modification of a similar table prepared by the American Institute of Steel Construction , which lists in ...
... weight of a concrete encasement d in lb / ft , and the product for checking lateral deflection when necessary . The bt table is a modification of a similar table prepared by the American Institute of Steel Construction , which lists in ...
Contents
APPENDIX B TABLES | 2 |
Shearing Stress | 10 |
SIMPLE STRAIN | 26 |
Copyright | |
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Common terms and phrases
acting actual allowable angle applied assumed axial axis beam beam shown bending bolt carries caused centroid circle column compressive compressive stress compute concentrated concrete consider constant couple cross section deflection deformation determine developed diagram diameter direction distance effect elastic curve element equal equation equivalent expressed flexural stress force formula ft-lb given gives Hence horizontal ILLUSTRATIVE inertia joint lb/ft length limit load material maximum method midspan moments negative neutral axis normal obtain occurs plane plate positive Prob PROBLEMS produce R₁ radius reaction relation resisting respect resultant rivet segment shaft shearing stress shown in Fig shows simply slope Solution Solve span spring steel strain strength supported Table tangent tensile thickness torque torsional uniformly varies vertical wall yield zero ΕΙ