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If the path is closed, the line integral is zero, r E-dl = Q (1.21) a result that can also
be obtained directly from Coulomb's law. Then application of Stokes's theorem [if
A(x) is a vector field, S is an open surface, and C is the closed curve bounding ...
The tangential component of electric field can be shown to be continuous across
a boundary surface by using (1.21) for the line integral of E around a closed path.
It is only necessary to take a rectangular path with negligible ends and one side ...
According to Ohm's law, there exists a current density J near the surface of the
conductor: J = aEc = (1 - 0(n x H^-W-<W (8.13) V 6TT The time-average rate of
dissipation of energy per unit volume in ohmic losses is £J • E* = (l/2<r) |J|2, so
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A soul crushing technical manual written by a sadist that has served as the right of passage for physics PhDs since the dawn of time. Every single one of my professors studied this book, and every ... Read full review
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"Jackson E&M is about learning how to approximate reliably...the entire book, with few exceptions, is a mathematical discussion on how to solve [the same] 4 problems for different boundary conditions." Read full review
Introduction to Electrostatics
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