## Classical Electrodynamics |

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Page 9

If the path is closed, the line integral is zero, jeal-o (1.21) a result that can also be

obtained directly from Coulomb's law. Then application of Stokes's theorem [if A(x

) is a vector field, S is an open

If the path is closed, the line integral is zero, jeal-o (1.21) a result that can also be

obtained directly from Coulomb's law. Then application of Stokes's theorem [if A(x

) is a vector field, S is an open

**surface**, and C is the closed curve bounding S, ...Page 10

The tangential component of electric field can be shown to be continuous across

a boundary

It is only necessary to take a rectangular path with negligible ends and one side ...

The tangential component of electric field can be shown to be continuous across

a boundary

**surface**by using (1.21) for the line integral of E around a closed path.It is only necessary to take a rectangular path with negligible ends and one side ...

Page 240

167 This is the same rate of energy dissipation as given by the Poynting's vector

result (8.12). The current density J is confined to such a small thickness just

below the

current ...

167 This is the same rate of energy dissipation as given by the Poynting's vector

result (8.12). The current density J is confined to such a small thickness just

below the

**surface**of the conductor that it is equivalent to an effective**surface**current ...

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### Contents

Introduction to Electrostatics | 1 |

BoundaryValue Problems in Electrostatics I | 26 |

References and suggested reading | 50 |

Copyright | |

16 other sections not shown

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