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If the path is closed, the line integral is zero, f -<fl = 0 (1.21) a result that can also
be obtained directly from Coulomb's law. Then application of Stokes's theorem [if
A(x) is a vector field, S is an open surface, and C is the closed curve bounding S,
The tangential component of electric field can be shown to be continuous across
a boundary surface by using (1.21) for the line integral of E around a closed path.
It is only necessary to take a rectangular path with negligible ends and one side ...
According to Ohm's law, there exists a current density J near the surface of the
conductor: J = <rEc = (1 - /)(n x HJe-t*-«" (8.13) The time-average rate of
dissipation of energy per unit volume in ohmic losses is JJ • E* = (l/2<r) |J|2, so
that the total ...
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Introduction to Electrostatics
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