## Classical Electrodynamics |

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Results 1-3 of 98

Page 9

If the path is closed, the line integral is zero, jeal-o - (1.21) a result that can also

be obtained directly from Coulomb's law. Then application of Stokes's theorem [if

A(x) is a vector field, S is an open

...

If the path is closed, the line integral is zero, jeal-o - (1.21) a result that can also

be obtained directly from Coulomb's law. Then application of Stokes's theorem [if

A(x) is a vector field, S is an open

**surface**, and C is the closed curve bounding S,...

Page 10

The tangential component of electric field can be shown to be continuous across

a boundary

It is only necessary to take a rectangular path with negligible ends and one side ...

The tangential component of electric field can be shown to be continuous across

a boundary

**surface**by using (1.21) for the line integral of E around a closed path.It is only necessary to take a rectangular path with negligible ends and one side ...

Page 240

0 87 0 16m This is the same rate of energy dissipation as given by the Poynting's

vector result (8.12). The current density J is confined to such a small thickness

just below the

...

0 87 0 16m This is the same rate of energy dissipation as given by the Poynting's

vector result (8.12). The current density J is confined to such a small thickness

just below the

**surface**of the conductor that it is equivalent to an effective**surface**...

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### Contents

Introduction to Electrostatics | 1 |

References and suggested reading | 23 |

Multipoles Electrostatics of Macroscopic Media | 98 |

Copyright | |

6 other sections not shown

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