## Electromagnetic fieldsThis revised edition provides patient guidance in its clear and organized presentation of problems. It is rich in variety, large in number and provides very careful treatment of relativity. One outstanding feature is the inclusion of simple, standard examples demonstrated in different methods that will allow students to enhance and understand their calculating abilities. There are over 145 worked examples; virtually all of the standard problems are included. |

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Page 12

In fact, du du = — — dx + dx du du — dy + —dz ay dz (1-35) where we should

remember that the derivatives are evaluated at the original point, that is, du/dx = (

du/dx)P, and so on. Although we have

...

In fact, du du = — — dx + dx du du — dy + —dz ay dz (1-35) where we should

remember that the derivatives are evaluated at the original point, that is, du/dx = (

du/dx)P, and so on. Although we have

**written**the displacement as ds, it is clearly...

Page 114

When this is inserted into (8-7), we find that the dipole term can be

terms of the dipole moment as p . ? p . r *'>(0 = 1 1 = 7 J (8-21) We note that (8-21

) has the form of a (scalar) product of quantities, one of which depends only on

the ...

When this is inserted into (8-7), we find that the dipole term can be

**written**interms of the dipole moment as p . ? p . r *'>(0 = 1 1 = 7 J (8-21) We note that (8-21

) has the form of a (scalar) product of quantities, one of which depends only on

the ...

Page 125

The first bracketed term in (8-61) can be

because of (5-3) where E0 is the external electric field. Since E0 is a constant

also, when we put (8-63) into (8-60) we get this contribution to the energy as Van-

-E0- ...

The first bracketed term in (8-61) can be

**written**as ""/. (v</>0)o= -r,-E0 (8-63)because of (5-3) where E0 is the external electric field. Since E0 is a constant

also, when we put (8-63) into (8-60) we get this contribution to the energy as Van-

-E0- ...

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angle assume axes axis becomes bound charge boundary conditions bounding surface calculate capacitance capacitor cavity charge density charge distribution charge q circuit conductor const constant convenient corresponding Coulomb's law current density curve cylinder defined dielectric dipole direction displacement distance divergence theorem electric field electromagnetic electrostatic energy equal equipotential evaluate example Exercise expression field point flux force free charge frequency function given illustrated in Figure induction infinitely long integral integrand Laplace's equation line charge line integral located Lorentz transformation magnetic magnitude Maxwell's equations obtained origin parallel particle perpendicular plane wave plates point charge polarized position vector potential difference quantities rectangular coordinates region result scalar potential shown in Figure solenoid sphere of radius spherical surface integral tangential components theorem total charge unit vectors vacuum vector potential velocity volume write written xy plane zero