Engineering Mechanics of Materials |
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Page 627
... solve Example 13.5 again . Compare your answers with the answers for Example 13.5 . 13.4 Solve Example 13.6 by assuming that the im- pacted beam is simply supported rather than fixed- ended . Compare your answers with the answers for ...
... solve Example 13.5 again . Compare your answers with the answers for Example 13.5 . 13.4 Solve Example 13.6 by assuming that the im- pacted beam is simply supported rather than fixed- ended . Compare your answers with the answers for ...
Page 647
... Solve Problem 13.34 for compressive forces and plot the Goodman straight line in the appro- priate quadrant . Assume the member is short enough that buckling is not a problem . 13.37 Solve Problem 13.35 for compressive forces and plot ...
... Solve Problem 13.34 for compressive forces and plot the Goodman straight line in the appro- priate quadrant . Assume the member is short enough that buckling is not a problem . 13.37 Solve Problem 13.35 for compressive forces and plot ...
Page 714
... solve for MA and V , by dealing with a 2 × 2 system . Use the method of two successive integrations to formulate the equations . Determine M , and VÅ using the equations of statics . 14.67 Refer to Figure 14.24 ( a ) and remove MB at ...
... solve for MA and V , by dealing with a 2 × 2 system . Use the method of two successive integrations to formulate the equations . Determine M , and VÅ using the equations of statics . 14.67 Refer to Figure 14.24 ( a ) and remove MB at ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁