Engineering Mechanics of Materials |
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Page 452
... aluminum rods at B and C as shown . The length I of the aluminum rods is 20 in . and their cross - sectional area A is 1 in.2 . Other needed dimensions are shown in Figure 9.5 ( a ) . Assume the coefficient of thermal expansion for ...
... aluminum rods at B and C as shown . The length I of the aluminum rods is 20 in . and their cross - sectional area A is 1 in.2 . Other needed dimensions are shown in Figure 9.5 ( a ) . Assume the coefficient of thermal expansion for ...
Page 630
... aluminum and steel beams are 70 GPa and 200 GPa , respectively . Neglect energy lost during impact . Use h = 0.02 m . 13.25 An aluminum beam and a steel beam are simply supported at their ends and subjected to an impact loading by ...
... aluminum and steel beams are 70 GPa and 200 GPa , respectively . Neglect energy lost during impact . Use h = 0.02 m . 13.25 An aluminum beam and a steel beam are simply supported at their ends and subjected to an impact loading by ...
Page 685
... aluminum and in the brass . Solve the problem by transforming the brass into aluminum . Determine also the deflection at the end of the cantilever . 14.27 Repeat Problem 14.26 by transforming the aluminum into brass . 14.28 A ...
... aluminum and in the brass . Solve the problem by transforming the brass into aluminum . Determine also the deflection at the end of the cantilever . 14.27 Repeat Problem 14.26 by transforming the aluminum into brass . 14.28 A ...
Contents
Internal Forces in Members | 1 |
Stress Strain and Their Relationships | 53 |
Stresses and Strains in Axially Loaded Members | 115 |
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absolute maximum shear aluminum angle of twist applied Assume axes axial force axially loaded beam shown bending C₁ cantilever beam Castigliano's second theorem column compressive Compute coordinate cross section cross-sectional area cylinder deflection deformation depicted in Figure Determine diameter elastic curve equal equation equilibrium Example factor of safety flexural stress free-body diagram Homework Problems k-ft k-in kN-m length M₁ material maximum shear stress MN/m² modulus of elasticity Mohr's circle moment of inertia neutral axis normal stress obtained perpendicular plane stress plot principal centroidal axis principal stresses r₁ ratio Refer to Figure respect rotation section a-a shaft shear strain shown in Figure slope Solution Solve static statically indeterminate steel stress at point stress condition stress element T₁ tensile tension Tmax torque torsional V₁ yield strength yield stress zero σ₁